I want to open FormStatus in a new page when I click a button in Form page.
Below is my code.
App.js:
import Form from "./components/Form";
import FormStatus from "./components/FormStatus";
import { BrowserRouter as Router, Route } from "react-router-dom";
function App() {
return (
<Router>
<div className="App">
<Route path="/" component={Form}/>
<Route exact path="/form-status" component={FormStatus}/>
</div>
</Router>
);
}
export default App;
Form.js
import { Link } from "react-router-dom";
const Form = () => {
return (
<div>
<h1>Form Page</h1>
<Link to="/form-status"><button>click</button></Link>
</div>
);
}
export default Form;
FormStatus.js:
import React, {Component} from "react";
class FormStatus extends Component {
render(){
return(
<h1>Form Status Page</h1>
)
}
}
export default FormStatus;
when I click on the button on Form component, my url changes to http://localhost:3000/form-status,
but instead of opening a new page, my FormStatus component comes below Form component.
I want FormStatus to open new a page and only shows contents of my FormStatus component and not contents of Form component
<Link to="/form-status" target="_blank"><button>click</button></Link>?