Java Integer object instantiation with parameters [duplicate]

Question

This question is a part of OCP test series .

> Integer i=new Integer(100_00);

I tried to understand how this works but so far i have only got this much that this is one of a message format . Please provide some clarity as to how we can pass a numeric value with a underscore . Pardon me if this is a simple concept but i am kind of anxious to know this .

Jigar Joshi · Accepted Answer · 2018-05-22 23:08:50Z

5

Java allows numeric literals with _ for better readability.

For example:

int i = 10_000;
float pi =      3.14_15F;

answered May 22, 2018 at 23:08

Jigar Joshi

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5 Comments

Kevin Anderson Over a year ago

In other words, 10_000, 100_00 and 10000 are all the same; they all mean "ten thousand".

Nishant_Singh Over a year ago

Thanks Jigar and Kevin . Your answers combined answer this . So this is just for readability . After your code gets compiled, these underscores are removed in bytecode stream ?

Louis Wasserman Over a year ago

The compilation process itself deals with the underscores.

Nishant_Singh Over a year ago

I am sorry deals ?

Jigar Joshi Over a year ago

correct, int i = 100 and int i = 1_0_0 compiles to same thing

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