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We consider an $n$-dimensional Riemannian manifold $M$ (not necessarily compact) without boundary. Following the paper ''Heat semigroup and functions of bounded variation on Riemannian manifolds'' by Miranda et al., one can define the variation of a function $u \in L^1(M)$ as a measure given on $M$ by

$$ |D u|(M):=\sup \left\{\int_M u \operatorname{div} \omega \mathrm{~d} V_g: \omega \in \Gamma_c(T^* M),|\omega(x)|_g \leqslant 1 \text { for all } x \in M\right\}, $$

where $\Gamma_c(T^* M)$ denotes the space of all compactly supported $C^{\infty}$ vector fields. We say that $u$ is of bounded variation and write $u \in B V(M)$, if $|D u|(M)<\infty$. Taking a measurable set $E \subset M$, we denote the perimeter of $E$ in a Borel set $A$ by

$$ P(E, A)=\left|D 1_E\right|(A), $$ where $1_E$ is the characteristic function of $E$. Now, we recall the coarea formula for BV functions in the Euclidean case ($\Omega$ is an open set in $\mathbb{R}^n$), which says that for any $u \in \operatorname{BV}(\Omega)$, denoting $E_t:=\{x \in \Omega: u(x)>t\}, t \in \mathbb{R}$, it holds:

$$ |D u|(\Omega)=\int_{-\infty}^{\infty} P\left(E_t, \Omega\right) d t. $$

Is the same true also in the manifold case? Can you provide a reference about that?

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    $\begingroup$ Miranda wrote this beautiful paper about BV functions on metric measure spaces, and there you can find a coarea formula: zbmath.org/1109.46030 $\endgroup$ Commented May 23 at 15:56
  • $\begingroup$ @Seba thanks for the tip. Indeed, these ‘’good’’ metric spaces clearly cover also the Riemannian manifold case. I also need the notion of simple set, in this case. It’s not in this Miranda paper, do you have another reference where I can find it? $\endgroup$ Commented May 23 at 19:11
  • $\begingroup$ I don't know what is a simple set: could you explain please? By the way, I have been told that the coarea formula in Miranda's paper is proven without using doubling condition or Poincaré inequality; so, it seems to hold on every metric measure space. $\endgroup$ Commented May 25 at 6:58
  • $\begingroup$ @Seba thanks again, that's even better. In Section 5, Definition (3), in this paper of Ambrosio et al. ems.press/journals/jems/articles/120. Another beautiful paper. Any indecomposable and saturated subset of $\mathbb{R}^{\mathrm{N}}$ is simple. The definition of indecomposability and saturation are in the same paper. $\endgroup$ Commented May 25 at 10:37

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