I want to control the amount of current going through a Triac by adjusting the firing angle accordingly. The Circuit is shown below:
Let's say i want IRMS to be 0.28A then the controller need to change α to be 90° according the formula:
My problem is I can't derive the Transfer function in order to calculate the needed parameters. Here is what i got so far: $$u(t)in = Vmax.sin(ωt)$$ can also be described as: $$u(t)in = i(t)R + L\frac{di}{dt}$$ Laplace Transformation gives: $$Vmax \frac{ω}{s²+ω²} = iR + L s i$$ Then the Transfer function of the RL load is: $$G(s) = \frac{i}{Vmax} = \frac{\frac{ω}{s²+ω²}}{R+Ls}$$ I am stuck here. There is no Correlation with α and the function is too complicated. The controller i am planning to use is a PT1 Controller with the following transfer function: $$G(s) = \frac{K}{1+Ts}$$ At the end this will be programmed inside a Raspi Pico W. Can anyone shed some light on this?
EDIT:
using the values provided by @Transisor comment I managed to get the following equation: $$Vrms = Vpeak(-0,2552\alpha + 0,832726)$$ doing a laplace transformation gives: $$ -0.2552Vpeak \cdot \alpha + \frac {0.832726Vpeak}{s} = I(s) \cdot R + L \cdot sI(s)$$ I have neglected $$\frac {0.832726Vpeak}{s}$$ to make the system a LTI system and got: $$G_s(S) = \frac{I}{\alpha} = \frac{-0,2552 \hat{V}/R}{1 + \frac{L}{R}s}$$ does this make sense? can I keep going from here?


