How to get source of function in Julia?

Question

How to get source of function for report generation, without copy pasting?

code(text) = println(text)

μ_model(period, vol_q, Q) = begin
  lp = log(period)
  exp(Q[1] + Q[2]lp + Q[3]vol_q)
end

code(source(μ_model))

That would produce same effect as copy paste

code("""
  μ_model(period, vol_q, Q) = begin
    lp = log(period)
    exp(Q[1] + Q[2]lp + Q[3]vol_q)
  end
""")

tholy · Accepted Answer · 2025-09-17 23:47:47Z

4

See CodeTracking.jl, specifically its @code_string.

answered Sep 17 at 23:47

tholy

12.3k2 gold badges31 silver badges42 bronze badges

Sign up to request clarification or add additional context in comments.

Comments

Jason D · Accepted Answer · 2025-09-18 09:58:51Z

2

@less μ_model(period, vol_q, Q)

This will show function source code if it's defined in an included file. You need to provide actual parameters to let Julia detect what types it's calling.

Then it's vim. Use :q to exit.

answered Sep 18 at 9:58

Jason D

3232 silver badges7 bronze badges

Collectives™ on Stack Overflow

How to get source of function in Julia?

2 Answers 2

Comments

Comments

Your Answer

Hot Network Questions

Collectives™ on Stack Overflow

2 Answers 2

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Related