How do I pass variable keyword arguments to a function in Python?

Question

How can I pass dictionary keys (or other attributes/values) as keywords for keyword arguments?

The function I want to pass arguments to takes keyword arguments:

func(arg1= "foo", arg_a= "bar", firstarg= 1)

I have a lot of arguments to pass to it, so I'd like to loop it (or if it's possible without a loop, even better):

arguments_dictionary={'arg1': "foo", 
                      'arg_a': "bar",
                       ...}

for keyword, value in arguments_dictionary.items():
  func(keyword= value)

Sadly, keyword= is not recognized as 'arg1'. How can I make this work?

func(**arguments_dictionary)... Remove the loop

OneCricketeer
– OneCricketeer

2018-06-22 13:48:26 +00:00
Commented Jun 22, 2018 at 13:48 — OneCricketeer
– OneCricketeer, Commented Jun 22, 2018 at 13:48

Cribber · Accepted Answer · 2023-05-27 06:46:35Z

13

Assuming you want to call func a single time:

def func(arg1="foo", arg_a= "bar", first_arg=1):
   print(arg1, arg_a, first_arg)

arguments_dictionary = {
  'arg1': "foo", 
  'arg_a': "bar",
  'first_arg':42
   }

func(**arguments_dictionary)

edited May 27, 2023 at 6:46

Cribber

3,0133 gold badges38 silver badges86 bronze badges

answered Jun 22, 2018 at 13:48

bruno desthuilliers

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2 Comments

bruno desthuilliers Over a year ago

Strange how SO works... Sometimes you take hours writing a clear, detailed answer with in-depth explanations of some arcane feature and don't even get an upvote, then you write a minimal answer on a beginner-level question and get five upvotes in a couple minutes <g>

Daniel Over a year ago

SO is fundamentally broken for just that. It's simply too large of a community for its own good.

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