Incompatible assignment to enum from enum *

Question

My code got an error below: incompatible types when assigning to type enum cell from type enum cell *

I have tried many ways to fix it but didnt work. This is my code:

BOOLEAN init_first_player(struct player * first, enum cell * token) {
    strcpy(first->name, "Bob");
    first->score = 0;

    int colorNo = rand() % 2;
    token = (colorNo + 1 == 1) ? RED : BLUE;

    first->token = token; //Error occurs here
    return TRUE;
}

this is my data structure:

struct Player {
    char name[20];
    enum cell token; //takes 0 - 1 - 2
    unsigned score;
};

enum cell {
    BLANK, RED, BLUE
};

Someone can please fix the code as I don't know what I have been doing wrong.

Why are you passing enum cell * token to the function when all you do with it is use it like a local variable? — user3386109
– user3386109, Commented Aug 11, 2016 at 5:07
How is init_first_player()called, what are you passing and how are those values defined and initialised? — alk
– alk, Commented Aug 11, 2016 at 5:11
Do you know the difference between a pointer and a thing that is not a pointer? — Stack Exchange Broke The Law
– Stack Exchange Broke The Law, Commented Aug 11, 2016 at 6:28

Chad · Accepted Answer · 2016-08-11 05:05:27Z

2

You are passing token in as a pointer, presumably because you want to see the modified value at the call site. (If you don't care about the modified value, you shouldn't send it in this function at all).

So, you need to dereference it when assigning:

// use *token (instead of just token) to dereference and assign
*token = (colorNo + 1 == 1) ? RED : BLUE;

Same when assigning it to first->token:

first->token = *token;

answered Aug 11, 2016 at 5:05

Chad

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1 Comment

Jay Nguyen Over a year ago

Thank you very much

Rishikesh Raje · Accepted Answer · 2016-08-11 05:04:22Z

1

In init_first_player token is a pointer to enum

In your structure first, token is an enum.

You cannot assign a pointer to enum to an enum.

You should use

*token = (colorNo + 1 == 1) ? RED : BLUE;
first->token = *token

answered Aug 11, 2016 at 5:04

Rishikesh Raje

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