Checking condition while Exception handling in python

Question

This is part of my code in python. I want to check the error message and if HTTPError() then I want to add the host to the file ok.txt. But it doesn't work. what is the problem here?

except urllib2.URLError, e:
        print '%-15s\t%15r' % (url.strip(), e)
        if e == 'HTTPError()':
            OK.write('%-15s' % (url.strip()) + '\n')
            OK.flush()

When I run whole script the output is something like this:

http://a.com        HTTPError()
http://b.com    URLError(timeout('timed out',),)
http://c.com    URLError(timeout('timed out',),)
http://d.com    URLError(error(111, 'Connection refused'),)
http://e.com           200

msvalkon · Accepted Answer · 2014-07-01 07:54:57Z

3

Use isinstance() to check whether or not your error is of type HTTPError:

except urllib2.URLError as e: # use the "as e" instead of the old style comma delimitation.
    print '%-15s\t%15r' % (url.strip(), e)
    if isinstance(e, HTTPError):
        OK.write('%-15s' % (url.strip()) + '\n')
        OK.flush()

answered Jul 1, 2014 at 7:54

msvalkon

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2 Comments

msvalkon Over a year ago

Because HTTPError() calls the exception class. In effect it creates a new exception object but does not raise it. HTTPError is the type, which you can check against.

MLSC Over a year ago

Thank you... I am checking your solution

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