Passing a pointer to function as a parameter to other function with multiple arguments

Question

I would like to know how i can pass a pointer to a function to another function as a parameter, only the function that i wish to pass has multiple parameters. For example, my main function:

void main_func(float **D, float **w , int n, Pointer_to_func)

The function that i want to pass:

float func(int x_1, int y_1, int x_2, int y_2 ,int q)

Thanks.

Hint: use typedefs to stop the syntax getting too hairy.

Paul R
– Paul R

2013-01-15 18:32:54 +00:00
Commented Jan 15, 2013 at 18:32 — Paul R
– Paul R, Commented Jan 15, 2013 at 18:32

user529758 · Accepted Answer · 2013-01-15 18:42:11Z

1

Or without a typedef (just for completeness, you generally do want the typedef):

void main_func(float **D, float **w , int n, float (*callback)(int, int, int, int, int));

answered Jan 15, 2013 at 18:42

user529758

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1 Comment

OlejkaKL Over a year ago

woops..Your answers were alike..so i tagged it by mistake.

zch · Accepted Answer · 2013-01-15 18:35:25Z

1

typedef float (*func_t)(int x_1, int y_1, int x_2, int y_2 ,int q);
void main_func(float **D, float **w , int n, func_t callback)

answered Jan 15, 2013 at 18:35

zch

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1 Comment

OlejkaKL Over a year ago

Thanks. Learned something. :)

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