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Questions tagged [binomial-coefficients]

For questions that explicitly reference the binomial coefficients, Pascal's Triangle, and Binomial identities.

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6 votes
2 answers
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Dear mathematicians, I am a computer scientist wandering in the deep sea of combinatorics and asymptotics to pursue a recent interest in average case analysis of algorithms. In doing so, I designed ...
Christian Rinderknecht's user avatar
10 votes
3 answers
1k views

Is there a function $p:\mathbb N\to \{ 1,-1 \} $ and a fixed $N\in \mathbb N$ such that for every $n \geq N$ we get: $\sum _{i=0} ^{n} p(i)\binom {n}{i}=0$ ? Obviously $p(i)=(-1)^i$ works for $N=1$...
Shir's user avatar
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3 votes
1 answer
1k views

Let $k,p$ be positive integers. Is there a closed form for the sums $$\sum_{i=0}^{p} \binom{k}{i} \binom{k+p-i}{p-i}\text{, or}$$ $$\sum_{i=0}^{p} \binom{k-1}{i} \binom{k+p-i}{p-i}\text{?}$$ (...
Manolito Pérez's user avatar
2 votes
1 answer
367 views

Is there a general method for finding upper bounds of hypergeometric sums? The sum in particular I am trying to bound is $\sum_{j=1}^{k}\binom{k-1}{j-1}\binom{n-k-1}{j-1}4^{k-j}$. This is a ...
bandini's user avatar
  • 491
0 votes
2 answers
1k views

Does anyone know of a closed formula for $\displaystyle \cos\left(\sum_{n=0}^m a_n\right)$? I've seen formulas for $\displaystyle \cos\left(\sum_{n=0}^\infty a_n\right)$ and $ \displaystyle \tan\left(\...
Jackson Walters's user avatar
9 votes
3 answers
2k views

I know Vandermonde's convolution for binomial coefficients: $$\sum_{j=0...k} \binom{n}{j} \binom{m}{k-j} = \binom{n+m}{k}$$ Is there a similar multiplicative convolution? More precisely, is there a ...
Hoffjan's user avatar
  • 93
5 votes
1 answer
4k views

Any hexagon in Pascal's triangle, whose vertices are 6 binomial coefficients surrounding any entry, has the property that: the product of non-adjacent vertices is constant. the greatest common ...
milcak's user avatar
  • 159
23 votes
8 answers
14k views

Hi! I'm new here. It would be awesome if someone knows a good answer. Is there a good lower bound for the tail of sums of binomial coefficients? I'm particularly interested in the simplest case $\...
user13006's user avatar
  • 263
7 votes
0 answers
1k views

Let $a(n,k)=(-1)^k {{2n-k}\choose k}$ for $0 \le k \le n$ and $a(n,k)=0$ else. Then it is known (cf. OEIS A005439 and A098435) that the first column of the inverse matrix of $(a(i,j))_{i,j\ge0}$ is ...
Johann Cigler's user avatar
9 votes
2 answers
945 views

(I posted this question on Math.SE a few weeks ago. I got a few comments, but nothing definite, and so I thought I would try MO.) The origin of this question is the identity $$\sum_{k=0}^n \binom{n}{...
Mike Spivey's user avatar
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6 votes
1 answer
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While skimming the book Concrete Mathematics, (edit: first edition) I came across the following problem, which is listed there as a Research Problem: (Chapter 5, Exercise 96) Is ${2n \choose n}$ ...
Suvrit's user avatar
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3 votes
2 answers
2k views

I encountered with a recursive formula of the following kind: $$A(0,x)=1$$ $$A(n,x)= \sum _{j=0}^{n-1} \binom{n-1}{j} A(n-j-1,x) \sum _{k=0}^{x-1} A(j,k)$$ The sum terms can be re-arranged so to ...
Anixx's user avatar
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9 votes
3 answers
2k views

What is known about explicit (not necessarily closed-form) solutions to the recurrence $$R^n_k= (\alpha n) R^{n-1}_k + (\alpha' n + \beta' k) R^{n-1} _{k-1},$$ with initial condition $R_0^0 = 1$ and ...
Mike Spivey's user avatar
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18 votes
1 answer
2k views

Given positive integers $n$ and $d$, let $S$ indicate the list of all $d$-tuples of non-negative integers $(c_1,\ldots,c_d)$ such that $c_1+\cdots+c_d=n$. Let $v_i$ be the value of the multinomial ...
Yaroslav Bulatov's user avatar
4 votes
2 answers
10k views

I would like to ask whether there is a combinatorial proof of the following recurrence relation for Catalan numbers: $$ C_{n+1}=\frac{4n+2}{n+2} C_n. $$ Thanks!~
Thomas Li's user avatar
  • 459
9 votes
1 answer
2k views

I am interested in finding a lower bound of the sum: $$\sum_{i=0}^d \left(\genfrac{}{}{0pt}{}{n}{i}\right) \left(\genfrac{}{}{0pt}{}{m}{k-i}\right)$$ when $d < k$ (and assuming both $n\geq k$, $m\...
Carla's user avatar
  • 91
26 votes
3 answers
4k views

I am trying to prove $\sum\limits_{j=0}^{k-1}(-1)^{j+1}(k-j)^{2k-2} \binom{2k+1}{j} \ge 0$. This inequality has been verified by computer for $k\le40$. Some clues that might work (kindly provided by ...
Alexandra Seceleanu's user avatar
1 vote
2 answers
3k views

How can one show $\displaystyle\frac{(m+n-1)!}{m ! (n-1)!}\leq \left[\frac{e (m+n-1)}{n}\right]^{n-1}$ ?
Vagabond's user avatar
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35 votes
3 answers
3k views

This is an extract from Apéry's biography (which some of the people have already enjoyed in this answer). During a mathematician's dinner in Kingston, Canada, in 1979, the conversation turned to ...
Wadim Zudilin's user avatar
13 votes
4 answers
2k views

Skip Garibaldi asks if there is an elementary proof of the following fact that "accidentally" fell out of some high-powered machinery he was working on. Say that two matrices $A$ and $B$ over the ...
Timothy Chow's user avatar
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48 votes
5 answers
6k views

This historical question recalls Pafnuty Chebyshev's estimates for the prime distribution function. In his derivation Chebyshev used the factorial ratio sequence $$ u_n=\frac{(30n)!n!}{(15n)!(10n)!(6n)...
Wadim Zudilin's user avatar
18 votes
2 answers
3k views

One of the recent questions, in fact the answer to it, reminded me about the binomial sequence $$ a_n=\sum_{k=0}^n{\binom{n}{k}}^2{\binom{n+k}{k}}^2, \qquad n=0,1,2,\dots, $$ of the Apéry ...
Wadim Zudilin's user avatar
10 votes
3 answers
2k views

For each $d$, I have a matrix $M$ with values $$ M_{ij} = \begin{cases} \frac{4ij}{d} - \binom{2d}{d} & i \neq j & \\\\ \frac{4i^2}{d} - \binom{2d}{d} - \...
bandini's user avatar
  • 491
128 votes
17 answers
105k views

I am interested in the function $$f(N,k)=\sum_{i=0}^{k} {N \choose i}$$ for fixed $N$ and $0 \leq k \leq N $. Obviously it equals 1 for $k = 0$ and $2^{N}$ for $k = N$, but are there any other ...
mathy's user avatar
  • 1,358
13 votes
5 answers
2k views

Tony Lezard asked me the following question which seemed like it should not be too hard but which I did not immediately see how to answer. Define $f(n,k)$ recursively by $f(1,k) = 1$ and $$f(n,k) = \...
Timothy Chow's user avatar
  • 88.3k
2 votes
3 answers
701 views

I've recently come across a variant of the binomial polynomials, and I'm curious if anyone has seen these before. If so, I'd love a reference, a name, etc. First recall the following. If z is a ...
Daniel Erman's user avatar
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