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Let given $p,q \in \mathbb{Z}^+,r \in \mathbb{Z}$ and equation $p x^2 + q y^2 = z^3 + r$.

If exist solutions of Pell equation $qb^2-3pa^2=r\pm1$, then

$x = a(pa^2 - 3qb^2 + 3r)\\ y = b\\z = pa^2 + qb^2 - r$

Exist other Pell-kind parametrization of source equation with more symmetrical formulas for $x,y$?

The context of the question is related to the sum of cubes problem.

$u^3+v^3-z^3=r \implies u^3+v^3=z^3+r=px^2+qy^2$

For known $r$ and "big" $z$ and unknown $x,y$ equation $z^3+r=px^2+qy^2$ is always solvable for some "small" $p,q$.

For known $p,q,r$ and unknown $x,y,z$ equation $z^3+r=px^2+qy^2$ is solvable by Pell-like parametrization.

For known $z$ validity check $u,v$ is fast.

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  • $\begingroup$ If $p=q=1$ and $r$ is any fixed Integer then equation has infinitely many Solutions. If $r=0$ and for any fixed Integers $p$ and $q$ then equation has Infinitely many solutions. $\endgroup$ Commented Nov 8 at 18:27

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