I think I'm overlooking something very basic in this problem but I'm having trouble determining what that is! I'm pretty sure the issue is stemming from my equation for mesh 1, but the assumption I made about what \$I_x\$ is might also be incorrect.
I got the following equations:
$$ 4I_x + I_1(1-j) - I_2 + I_3 = 0 $$ $$ -I_1 + 2I_2 = -4 $$ $$ I_1(j) + I_3(1-j) = 4 $$
I also assumed that: \$I_x = I_2\$
I should get \$V_0 = 6.32 V\$, angle -18.43 degrees as my final answer, but I keep getting values that are way off!
The circuit diagram shows an AC steady-state circuit with three principal nodes and several components. It contains a current-dependent current source on the left with a value of \$4I_x\$, where \$I_x\$ is the current flowing down through a 1 Ω resistor on the bottom left. The circuit also includes three resistors (1 Ω, 1 Ω, and 1 Ω), a capacitor with an impedance of −j1 Ω, and an AC voltage source with a value of 4∠0∘ V placed in the lower-middle section. The voltage to be found, \$V_o\$, is defined across the rightmost 1 Ω resistor, which is connected between the top and bottom rails of the right-hand side of the circuit.





