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I have been referring research paper "Design of a Coreless Induction Furnace for Melting Iron" by M. M. Ahmed, M. Masoud and A. M. El-Sharkawy

(Refer https://s3.us-east-1.amazonaws.com/foundrygate-uploads/artigo_1678130244006_Design%20of%20a%20Coreless%20Induction%20Furnace%20for%20Melting%20Iron.pdf) (refer page 3)

Referring the paper I am stuck at this particular formula for effective value of emf created in element path of induction melting charge (refer marked in image)

Refer the equation for emf in particular element path as marked

I tried to break it down as below:

$$e=-\frac{dφ}{dt}$$

Where φ=BA, Assuming a sinusoidal variation of the magnetic field, $$B = B_m sin⁡(2πft)$$

Considering flux linkage of area related to displacement $x^2$, $$φ=B_m x^2 sin⁡(2πft)$$

Differentiating by dt, $$e=B_m x^2•(2πf)cos⁡(2πft)$$

Considering e(t)=E_m cos⁡(2πft) and E=E_m/√2 The peak EMF E_m $$E_m= 2πfx^2 B_m$$

Hence by that RMS of E, $$E= \frac{E_m}{√2} = \frac{2πfx^2 B_m}{√2}$$

However I cant gather the derivation of the another π in π^2 referred in the equation (shown in the pic) $$E= \frac{E_m}{√2} = \frac{2π^2fx^2 B_m}{√2}$$

for effective value of emf in subjected element path in the research paper as shown in the pic.

Would that have anything to do with sinusoidal motion displacement of the melting charge?

Any help is appreciated.

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    \$\begingroup\$ Eqn 15: Replace Omega with 2Pi.f. | Replace Cos(omega) with 1/sqrt(2). [No latex was harmed in the making of this comment]. Bed time \$\endgroup\$ Commented Apr 17 at 12:47

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I hope you have the understanding till the equation 13. In the next equation, the sin comes in picture for the flux linkage due to the sinusoidal nature of the flux to melt the metal. The A breaks into $$\pi x^2$$ for the circular surface area of the element. Differentiating the flux wrt time to obtain induced emf gives equation 15. Now omega w can be written as 2pif. Hence E_m can be written as $$E_m = 2π^2fx^2 B_m$$ Now as you mentioned putting value of E_m in below equation gives your answer. $$E= \frac{E_m}{√2}$$ Hope it helps.

P.S. Glad you tried to solve it using the basic formula your intuition wasn't totally incorrect.

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