Need to defer the `name` variable in a Bash script

Question

How to defer the name variable in our Bash script so that it expands correctly within quotes in the loop, in such e.g:

name='*'
curate() {
  local e=
  for e in $(export HOME='/home/me'; echo /home/me/Downloads/\${name}.$1)
  do
    [ -e "$e" ] && echo "$e"
  done
}

curate() c

name=foo
curate() c

as it didn't work.
Please help in clear way

curate() c - Sidenote, functions are called simply by invoking their names, i.e. without (). — Man made of meat
– Man made of meat, Commented Dec 11, 2024 at 4:39
Please edit your question and add your desired output (no description) for that sample input. — Cyrus
– Cyrus, Commented Dec 11, 2024 at 6:11
What do you expect setting HOME in your command substitution to accomplsh for you? — John Bollinger
– John Bollinger, Commented Dec 11, 2024 at 17:59
What do you expect the echo command in that same process substitution to accomplish for you, especially given that you are escaping the first $? — John Bollinger
– John Bollinger, Commented Dec 11, 2024 at 18:01
The result of a command substitution is not subject to variable expansion (during the processing of the same command). If that's what you're trying to accomplish then you'll need to find a different way. — John Bollinger
– John Bollinger, Commented Dec 11, 2024 at 18:16

jhnc · Accepted Answer · 2024-12-11 10:58:15Z

2

You can replace your curate function with:

curate() {
  local IFS= e=
  for e in /home/me/Downloads/$name.$1
  do
    [ -e "$e" ] && echo "$e"
  done
}

By localising IFS to empty string, glob expansion still happens but word-splitting of the result is disabled.

answered Dec 11, 2024 at 10:58

jhnc

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