How to declare a class that conforms to a protocol as parameter type?

Question

Is there a way to give, as a parameter, a class that conforms to a certain protocol?

What I tried at first, with a bit of hope, was this:

-(NSString *) getKeyForMyProtocolClass(Class<MyProtocol>)aClass

But that causes

[aClass superclass];

to give the warning "Instance method 'superclass' found instead of class method 'superclass'". I get the same sort of warning for conformsToProtocol:.

Since it gives no such warnings when the parameter is (Class)aClass, it seems Class< MyProtocol> is not actually of the Class type.

I should not be sending NSObject< MyProtocol>, since I need to determine the right key according to the class as well as its superclasses, and only create and add a new object if nothing is set to that key yet.

I could check with conformsToProtocol, but then I'd have to return a nil value which is just messy. I'd prefer to stop the issue at compile time.

So in short, is there a type declaration for a class that conforms to a protocol?

I have a class that can receive extensions that alter its behaviour. It stores its extensions in a dictionary, the key depends on the class. It has no knowledge of what classes can extend it. The key is the topmost superclass that implements the protocol, so that a class and its superclass won't be doing the same thing, also so other classes can ask if it has a certain extension without having to know all the subclasses of that extension's class. I have it all in place, except for the method signature which now forces me to return nil if the given class does not implement the protocol. — Aberrant
– Aberrant, Commented Oct 26, 2011 at 18:46
Notice: I haven't used Objective-C in a long time. I am not looking for the answer to this question anymore, nor do I feel qualified to judge and accept any answers. I think this question belongs to community votes at this point. — Aberrant
– Aberrant, Commented Jun 3, 2014 at 21:37

evanescent · Accepted Answer · 2014-03-21 03:20:28Z

1

You can just typecast your class object to prevent the compiler warning. I was able to do the following:

- (void)tempMethod:(Class<NSObject>)klass {
   id a = [(Class)klass superclass];
    NSLog(@"%@", a);
}

Since you know the type of the object(Class object) you're passing this should work fine.

answered Mar 21, 2014 at 3:20

evanescent

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