Bash assigning a variable to a command output which will be a list of multiple word strings [duplicate]

Question

This is the script which I am trying to run

bRules=(`aws s3api get-bucket-lifecycle-configuration --bucket x |  jq '.Rules[]'.ID`)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
for rule in "${bRules[@]}"
do
    echo "Bucket: x, Rule: $rule"
done

Actual output

*** Total number of LifecycleRules ****  6
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-1
 Bucket: x, Rule: This
 Bucket: x, Rule: is
 Bucket: x, Rule: Rule-2

Expected output:

*** Total number of LifecycleRules ****  2
Bucket: x, Rule: This is Rule-1
Bucket: x, Rule: This is Rule-2

What needs to be change in my code snippet to get the desired output? I'm kinda of lost to fix this issue.

konsolebox · Accepted Answer · 2022-01-06 07:14:21Z

1

Don't rely on command substitution and word splitting. Use readarray (or mapfile if you prefer) and process substitution instead.

Your loop can also be simplified to a single printf.

readarray -t bRules < <(aws s3api get-bucket-lifecycle-configuration --bucket x | jq '.Rules[]'.ID)
echo "*** Total number of LifecycleRules ****  ${#bRules[@]}"
printf 'Bucket: x, Rule: %s\n' "${bRules[@]}"

Read the Bash Manual.

answered Jan 6, 2022 at 7:14

konsolebox

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