If an object exists in JSON then print another value, if not, print nothing

Question

import requests

headers = {
    "User-Agent": "Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/91.0.4472.124 Safari/537.36"}

url = f'https:............'
response = requests.get(url, headers=headers).json()
events = response['events']
for event in events:
    List_of_Urls = []
    List_of_Urls.append(event['id'])

    slug = event['slug']

    for List_of_Url in List_of_Urls:
        try:
            url2 = f'https://.............../{List_of_Url}/.........'
            response2 = requests.get(url2, headers=headers).json()
            
            if response2['graphPoints']:
                print(slug)
        except:
            pass

Response JSON example 1:

{
  "graphPoints": [
    {
      "minute": 1,
      "value": -2
    }

Response JSON example 2:

{
  "error": {
    "code": 404,
    "message": "Not Found"
  }
}

My idea is that if there is graphPoints in JSON, then printing the slug value, but in the direct if response2['graphPoints']: value for true or false doesn't work, how should I make it work?

Why don't you just check for response code and ignore non 200? — jetpack_guy
– jetpack_guy, Commented Dec 6, 2021 at 20:29
besides the @chasmani's answer, there is also an option to exploit short-circuitry and just print(response2.get('graphPoints') and slug) — Marat
– Marat, Commented Dec 6, 2021 at 20:52

chasmani · Accepted Answer · 2021-12-07 10:24:18Z

1

If its a JSON object I think you can just do:

if 'graphPoints' in response2:
    print(slug)

edited Dec 7, 2021 at 10:24

answered Dec 6, 2021 at 20:31

chasmani

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6 Comments

Digital Farmer Over a year ago

Hello friend @chasmani , thanks for the support. I added two links inside a question to demonstrate the answers JSON gives. I tried the two ways you indicated but I was not successful!

Marat Over a year ago

the second one is an antipattern. key in some_dict is the intended way of checking dict membership

Marat Over a year ago

@BrondbyIF please post more information on how it doesn't work. The first snippet is actually the one you're looking for

Digital Farmer Over a year ago

Hi @Marat Actually I don't know why it's not working, the code runs and doesn't print any value, but when I use if (response2['graphPoints'][0]['minute'] >= 1):, then it returns the prints, so I work around the problem but I wanted something exact on top of the graphPoints existence

Marat Over a year ago

@BrondbyIF the answer contains a typo, graphpoints instead of graphPoints

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