I have 2 basic functions differ about type of parameter but code in these most of the same. Because i do not want to repeat code so i do:
bool func(std::string x)
{
if(x=="true")
return true;
return false;
}
bool func(int x)
{
if(x!=-1)
return true;
return false;
}
bool fun( auto x,bool (*f)(auto ))
{
return (*f)(x);
};
I have used auto keyword to be compatible with both functions, but it has something wrong so I need your supports.
You can use templates to implement fun:
template<typename T>
bool fun(T x, bool (*f)(T)) {
return f(x);
}
But while you're at it, you can also make fun a bit more generic. This way it also works with objects with a custom () operator (e.g. std::function, lambdas, ...):
template<typename T, typename F>
bool fun(T x, F f) {
return f(x);
}
You cannot use auto in function declaration, instead try to use templates something like this
bool func(std::string x)
{
if(x=="true")
return true;
return false;
}
bool func(int x)
{
if(x!=-1)
return true;
return false;
}
template<typename T>
bool fun(T x,bool (*f)(T))
{
return (*f)(x);
}
int main(int argc, char* argv[])
{
std::string str = "Test";
fun(str, func);
int x = 2;
fun(x, func);
return 0;
}
std::cout << (fun(str, func) ? "true" : "false") << '\n'; and the same for x to provide a bit of additional feedback on the operation?
if (x) return true; return false;can always be replaced withreturn (x);bool