React typescript test on enzyme doesn't simulate click

Question

I'm trying to simulate a click on a button but the test always fails and I have no idea why. It seems that enzyme can't select the DOM element to trigger a click on it, because the calls are always 0. I am using enzyme 3.7.0 and jest 23.6.0

Button.tsx

import * as React from 'react';
import './button.scss';

export interface IButton {
  value: string;
  onClick: () => void;
}

class Button extends React.Component<IButton, {}> {
  render() {
    return (
      <div className="Button">
        <button id="btn" onClick={this.props.onClick} className="Button__btn" type="button">
          {this.props.value}
        </button>
      </div>
    );
  }
}

export default Button;

Button.test.tsx

import * as React from 'react';
import { shallow } from 'enzyme';
import Button  from './Button';

test.only('Button test', () => {
  const myMock = jest.fn();

  const mockedButton = shallow(<Button value="testvalue" onClick={() => myMock} />);
  console.log(mockedButton.debug());

  // Interaction demo
  expect(mockedButton.text()).toEqual('testvalue');

  mockedButton.find('button').simulate('click');
  mockedButton.find('.Button__btn').simulate('click');
  mockedButton.find('button.Button__btn').simulate('click');
  expect(myMock.mock.calls.length).toBe(0); // !! Should be 3 ?

  // Snapshot demo
  expect(mockedButton).toMatchSnapshot();
});

However, the snapshot generated could allow me to select the right element (button)

exports[`Button test 1`] = `
<div
  className="Button"
>
  <button
    className="Button__btn"
    onClick={[Function]}
  >
    testvalue
  </button>
</div>
`;

skyboyer · Accepted Answer · 2018-10-10 09:12:13Z

2

The reason is this part:

onClick={() => myMock}

Here you describe click handler that returns your mock instead of calling it. It should be onClick={() => myMock()} or better just onClick={myMock}

instead. There React will call your myMock on .simulate('click')

answered Oct 10, 2018 at 9:12

skyboyer

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