Get index of array's object item by property and value

Question

I'm having troubles with updating found object. I also tried Find object by id in an array of JavaScript objects and Get JavaScript object from array of objects by value or property

Please help.

// Create array
var schedule = [];
schedule.push({ 'action': 'add', 'id': 1 });
schedule.push({ 'action': 'update', 'id': 2 });

// Find array object
var searchId = 2;
var foundObj = schedule.filter(function(obj) { return obj.id == searchId; })

// Update found object
if (typeof foundObj !== 'undefined') {
  var newId = 3;
  schedule[foundObj] = {'action': 'delete', 'id': newId };
}

console.log(schedule);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

foundObj will be array and not the index what do you want ?

Vinod Louis
– Vinod Louis

2017-01-20 13:22:38 +00:00
Commented Jan 20, 2017 at 13:22 — Vinod Louis
– Vinod Louis, Commented Jan 20, 2017 at 13:22
My question was hidden inside the code snippet. =)

scorpio1441
– scorpio1441

2017-01-20 13:23:58 +00:00
Commented Jan 20, 2017 at 13:23 — scorpio1441
– scorpio1441, Commented Jan 20, 2017 at 13:23

Vinod Louis · Accepted Answer · 2017-01-20 13:25:00Z

3

Use find to get the object and then use index of found object to replace element

// Create array
var schedule = [];
schedule.push({ 'action': 'add', 'id': 1 });
schedule.push({ 'action': 'update', 'id': 2 });

// Find array object
var searchId = 2;
var foundObj = schedule.find(function(obj) { return obj.id == searchId; })
// Update found object
if (typeof foundObj !== 'undefined') {
  var newId = 3;
  schedule[schedule.indexOf(foundObj )] = {'action': 'delete', 'id': newId };
}

console.log(schedule);

<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.1/jquery.min.js"></script>

answered Jan 20, 2017 at 13:25

Vinod Louis

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2 Comments

Alon Eitan Over a year ago

You already filtered the element, so you can update it directly instead of re-searching for its index

Alon Eitan Over a year ago

Yup, that's right - But at least you're demonstrating 2 possible solutions

Nina Scholz · Accepted Answer · 2017-01-20 13:25:07Z

1

You could use Array#find and check and update the properties.

var schedule = [{ action: 'add', id: 1 }, { action: 'update', id: 2 }],
    searchId = 2,
    newId = 3,
    foundObj = schedule.find(function(obj) { return obj.id == searchId; })

if (foundObj) {
    foundObj.action = 'delete';
    foundObj.id = newId;
}

console.log(schedule);

answered Jan 20, 2017 at 13:25

Nina Scholz

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