Javascript Random Number generate

Question

I want to generate random number between 0 to 100 and show a div tag if that random isn't less than 10. I have this code but it doesn't work, please can you help me fix the error.

I have already tried on google but I can not find code for php

function showbox(){
    document.getElementById("ap1").style.visibility = "visible";
}

function myFunction(name) {
    var x = document.getElementById("demo")
    x.innerHTML = Math.floor((Math.random() * 100) + 1);
}

if(myFunction(<=10){
    setTimeout(showbox, 35000);
}

<div id="ap1" style="visibility: hidden;"></div>

Check the console: Uncaught SyntaxError: Unexpected token <= — Andreas
– Andreas, Commented Jun 16, 2016 at 8:20

Mohammad · Accepted Answer · 2016-06-16 08:59:06Z

1

Your code has SyntaxError. You can use this code

var element = document.getElementById("ap1");
var random = Math.floor((Math.random() * 100) + 1);
element.innerHTML = random;

if (random >= 10){
    document.getElementById("ap1").style.visibility = "visible";   
} else
  console.log(random);

<div id="ap1" style="visibility: hidden;"></div>

Math.floor((Math.random() * 100) + 1) generate number between 1 and 100. If you want to generate number between 0 and 100 use Math.floor((Math.random() * 101)) or Math.round((Math.random() * 100))

edited Jun 16, 2016 at 8:59

answered Jun 16, 2016 at 8:26

Mohammad

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Comments

BenG · Accepted Answer · 2016-06-16 08:29:59Z

0

you need to close myFunction in the if and you need to return in myFunction:-

function showbox(){
    document.getElementById("ap1").style.visibility = "visible";
}

function myFunction(name) {
    var x = document.getElementById("ap1")
    return x.innerHTML = Math.floor((Math.random() * 100) + 1);
}

if(myFunction() <= 10){
    setTimeout(showbox, 35000);
}

<div id="ap1" style="visibility: hidden;"></div>

answered Jun 16, 2016 at 8:29

BenG

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Comments

István · Accepted Answer · 2016-06-16 10:11:44Z

0

Try this. The code wasn't correct. You used demo id but you have ap1, and the if condition also was wrong in JavaScript.

The JavaScript code:

function myFunction(name) {
  var x = document.getElementById("ap1")
  var randomNum = Math.floor((Math.random() * 100) + 1);
  if (randomNum > 10) {
    x.innerHTML = randomNum;
  } else {
    x.innerHTML = 'empty';
  }
}

setTimeout(myFunction, 350);

edited Jun 16, 2016 at 10:11

answered Jun 16, 2016 at 8:25

István

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