Calling C nested function pointer from Lua

Question

I have the following C struct, that contains function pointer:

struct db {
    struct db_impl *impl;
    void (*test)(struct db *self); // How to invoke it from Lua??
};
void (*db_test)(void); // this I can invoke from Lua

struct db * get_db() {
    // create and init db
    struct db * db = init ...
    db->test = &db_real_impl; // db_real_impl is some C function
    return db;
}

So the test function pointer after initialization points to some function. Now I need to call that function from Lua using FFI library, but it fails with error: 'void' is not callable.

local db = ffi.C.get_db()
db.test(db)  -- fails to invoke
-- Error message: 'void' is not callable

ffi.C.db_test()  -- this works fine

In C the code would be:

struct db *db = get_db();
db->test(db);

In Lua I'm able to invoke free function pointers easily, but can't invoke function pointer from struct. How to invoke it from Lua?

void (*db_test)(void); wrong prototype, should be void (*db_test)(struct db *); — David Ranieri
– David Ranieri, Commented May 4, 2016 at 8:29
no, it's not wrong. db_test is different function pointer, it does not have any args. It's not relevant to the question anyway — nogard
– nogard, Commented May 4, 2016 at 8:31
Just to show that I can easily call free function pointers, but not the nested one (that belongs to struct) — nogard
– nogard, Commented May 4, 2016 at 8:36
Are you assigning some function to test before calling it? db.test = somefunction — David Ranieri
– David Ranieri, Commented May 4, 2016 at 8:40

nogard · Accepted Answer · 2016-05-10 15:58:41Z

2

+50

A solution seems to be pointed out in : http://lua-users.org/lists/lua-l/2015-07/msg00172.html

ffi.cdef[[
    typedef void (*test)(struct db *);
]]

local db = get_db()
local call = ffi.cast("test", db.test)
call(db)

edited May 10, 2016 at 15:58

nogard

9,7667 gold badges36 silver badges53 bronze badges

answered May 10, 2016 at 15:26

Trop_Wizz

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