jQuery's tooltip with ajax request, how to trigger only once

Question

to sum it up quickly.. I have a jQuery tooltip on one of my table elements with a specific data attribute to select it. it works great, makes an ajax request, returns data and puts it in the tooltip. only problem is every time i mouse over the table element the ajax request gets triggered again.

    $('p').tooltip({ 
        items: "[data-whatever]",
        content: function(){
            var el = $(this),
                content = el.data('ajax-content');
            if(content)
                return content;    
            return 'waiting for ajax';
        },
        open: function(){
            var elem = $(this),
                id = elem.data('whatever');
            $.ajax('/echo/html/' + id).always(function(res)  {
                elem.tooltip('option', 'content', res[0].label);
                elem.data('ajax-content', res[0].label);
            });
        }
    });

all of this works fine ( i made a few changes to the code so its not identical to what i did because its incorporated into my works module pattern).. but is there a simple way to only hit the open function one time?

any help would be appreciated!

Zhivko Donev · Accepted Answer · 2014-05-07 16:27:39Z

1

You can check if 'ajax-context' data is already set. If so do not trigger the ajax request.

$('p').tooltip({ 
    items: "[data-whatever]",
    content: function(){
        var el = $(this),
            content = el.data('ajax-content');
        if(content)
            return content;    
        return 'waiting for ajax';
    },
    open: function(){
        var elem = $(this),
            label = elem.data('ajax-content');
        if (label) {
          elem.tooltip('option', 'content', label);
        } else {
          var id = elem.data('whatever');
            $.ajax('/echo/html/' + id).always(function(res)  {
                elem.tooltip('option', 'content', res[0].label);
                elem.data('ajax-content', res[0].label);
            });
        }
    }
});

answered May 7, 2014 at 16:27

Zhivko Donev

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1 Comment

John Ruddell Over a year ago

I ended up going with your answer as its a better practice to check in this way. thanks again

Rashmin Javiya · Accepted Answer · 2014-05-07 16:42:46Z

1

Try this, store ajax response in element data, now check in open event if tooltip exists in data, if yes show it else cal ajax.

$('p').tooltip({ 
    items: "[data-whatever]",
    content: function(){
        var el = $(this),
            content = el.data('ajax-content');
        if(content)
            return content;    
        return 'waiting for ajax';
    },
    open: function(){
        if($(this).data("ajax-content") == undefined) {
            var elem = $(this),
                id = elem.data('whatever');
            $.ajax('/echo/html/' + id).always(function(res)  {
                elem.tooltip('option', 'content', res[0].label);
                elem.data('ajax-content', res[0].label);
            });
        }
        else {
            $(this).tooltip('option', $(this).data("ajax-content"));
        }
    }
});

edited May 7, 2014 at 16:42

answered May 7, 2014 at 16:23

Rashmin Javiya

5,2223 gold badges31 silver badges49 bronze badges

5 Comments

John Ruddell Over a year ago

you were really close... .data('tooltip') needs to be ajax-content... and then in the else, elem is undefined so it needs to be $(this)

Rashmin Javiya Over a year ago

Yes, it was not tested, i was delivering my idea only. :)

John Ruddell Over a year ago

I know :) i was just telling you what needs to be fixed so I can accept the answer.. future ppl can see the correct answer

Rashmin Javiya Over a year ago

@JohnRuddell i have stored data in toolip, so i am fetching from toolip. pl check

John Ruddell Over a year ago

ah i see now... i use data-ajax in the content, so either the tooltip needs to be changed or the data-ajax.. either way should work.

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