jQuery same click event for multiple elements

Question

Is there any way to execute same code for different elements on the page?

$('.class1').click(function() {
   some_function();
});

$('.class2').click(function() {
   some_function();
});

instead to do something like:

$('.class1').$('.class2').click(function() {
   some_function();
});

David Harkness · Accepted Answer · 2019-03-05 20:51:09Z

999

$('.class1, .class2').on('click', some_function);

Or:

$('.class1').add('.class2').on('click', some_function);

This also works with existing objects:

const $class1 = $('.class1');
const $class2 = $('.class2');
$class1.add($class2).on('click', some_function);

edited Mar 5, 2019 at 20:51

David Harkness

36.6k11 gold badges119 silver badges136 bronze badges

answered Aug 21, 2009 at 18:03

Eevee

48.7k11 gold badges100 silver badges128 bronze badges

Sign up to request clarification or add additional context in comments.

9 Comments

Brett Weber Over a year ago

To help developers remember this, even if a bit more extended using more psuedo classes it is the same format as applying a css selector when defining styles

Vivek S Over a year ago

What if had class2 cached like this var class2=$(".class2")?

Eevee Over a year ago

@NeverBackDown .add() works with jquery objects too

Ben Sewards Over a year ago

Note that this will still attach events to jquery objects that exist, even if one of the selectors returns undefined.

Taufik Nur Rahmanda Over a year ago

can somebody explain what's the real difference between $('.class1, .class2') and $('.class1').add('.class2')? in what case we should use .add()?

|

The Codesee · Accepted Answer · 2020-09-05 13:05:32Z

149

I normally use on instead of click. It allow me to add more events listeners to a specific function.

$(document).on("click touchend", ".class1, .class2, .class3", function () {
     //do stuff
});

edited Sep 5, 2020 at 13:05

The Codesee

3,7937 gold badges44 silver badges80 bronze badges

answered Jul 11, 2014 at 11:13

bzin

2,0012 gold badges16 silver badges15 bronze badges

3 Comments

Gaurav Ojha Over a year ago

I like this way better. But can you target one element by class and one by ID in the same declaration? For e.g. $(document).on("click touchend", ".class1, #id1, .class3", function () { //do stuff });

Obed Parlapiano Over a year ago

a year later: yes, you can! @GauravOjha

Jonathan Lidbeck Over a year ago

This technique--creating a delegated, rather than direct handler--also offers the unique advantage of handling events triggered by matching elements created after registering the handler. See: api.jquery.com/on

adinas · Accepted Answer · 2019-05-08 13:13:18Z

50

$('.class1, .class2').click(some_function);

Make sure you put a space like $('.class1,space here.class2') or else it won't work.

edited May 8, 2019 at 13:13

adinas

4,5803 gold badges42 silver badges59 bronze badges

answered Aug 25, 2011 at 4:49

coolguy

7,9549 gold badges48 silver badges72 bronze badges

Comments

Dency G B · Accepted Answer · 2015-12-14 10:01:12Z

19

Simply use $('.myclass1, .myclass2, .myclass3') for multiple selectors. Also, you dont need lambda functions to bind an existing function to the click event.

edited Dec 14, 2015 at 10:01

Dency G B

8,16610 gold badges52 silver badges79 bronze badges

answered Aug 21, 2009 at 18:04

code_burgar

12.3k4 gold badges37 silver badges53 bronze badges

1 Comment

Maurizio In denmark Over a year ago

you need a space after the commas

pim · Accepted Answer · 2015-04-07 12:57:31Z

11

Another alternative, assuming your elements are stored as variables (which is often a good idea if you're accessing them multiple times in a function body):

function disableMinHeight() {
    var $html = $("html");
    var $body = $("body");
    var $slideout = $("#slideout");

    $html.add($body).add($slideout).css("min-height", 0);
};

Takes advantage of jQuery chaining and allows you to use references.

answered Apr 7, 2015 at 12:57

pim

12.7k6 gold badges71 silver badges70 bronze badges

Comments

frzsombor · Accepted Answer · 2019-03-21 11:41:44Z

9

If you have or want to keep your elements as variables (jQuery objects), you can also loop over them:

var $class1 = $('.class1');
var $class2 = $('.class2');

$([$class1,$class2]).each(function() {
    $(this).on('click', function(e) {
        some_function();
    });
});

answered Mar 21, 2019 at 11:41

frzsombor

2,6102 gold badges27 silver badges45 bronze badges

Comments

Nitin Pawar · Accepted Answer · 2016-12-28 06:43:02Z

5

We can code like following also, I have used blur event here.

$("#proprice, #proqty").blur(function(){
      var price=$("#proprice").val();
      var qty=$("#proqty").val();
      if(price != '' || qty != '')
      {
          $("#totalprice").val(qty*price);
      }
  });

answered Dec 28, 2016 at 6:43

Nitin Pawar

2635 silver badges12 bronze badges

Comments

user2589071 · Accepted Answer · 2017-09-26 06:20:40Z

4

Add a comma separated list of classes like this :

jQuery(document).ready(function($) {

$('.class, .id').click(function() { 

//  Your code

    }

});

answered Sep 26, 2017 at 6:20

user2589071

Comments

Andrii Bogachenko · Accepted Answer · 2016-12-01 09:38:44Z

1

I have a link to an object containig many input fields, which requires to be handled by the same event. So I simply use find() to get all the inside objects, that need to have the event

var form = $('<form></form>');
// ... apending several input fields

form.find('input').on('change', onInputChange);

In case your objects are one level down the link children() instead find() method can be used.

answered Dec 1, 2016 at 9:38

Andrii Bogachenko

1,30515 silver badges20 bronze badges

Comments

Arkhaine · Accepted Answer · 2017-07-24 05:10:38Z

1

In addition to the excellent examples and answers above, you can also do a "find" for two different elements using their classes. For example:

<div class="parent">
<div class="child1">Hello</div>
<div class="child2">World</div>
</div>

<script>
var x = jQuery('.parent').find('.child1, .child2').text();
console.log(x);
</script>

This should output "HelloWorld".

answered Jul 24, 2017 at 5:10

Arkhaine

1314 bronze badges

Collectives™ on Stack Overflow

jQuery same click event for multiple elements

10 Answers 10

9 Comments

3 Comments

Comments

1 Comment

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Linked

Hot Network Questions

Collectives™ on Stack Overflow

10 Answers 10

9 Comments

3 Comments

Comments

1 Comment

Comments

Comments

Comments

Comments

Comments

Comments

Your Answer

Sign up or log in

Post as a guest

Linked

Related