In a bash script file, is there a way that I can use command line arguments from within a function which has parameters?
Or do I need to assign all command line parameters to a variable for them to be accessible in the function body?
echo $1 # may be "abc"
function f() { $1; } # will be "def", but I need "abc" here
f "def"
PS: I found a similar question on stack overflow, but that question doesn't deal with the issue I describe here?
Just for the record, this is possible in extdebug mode through BASH_ARGC and BASH_ARGV variables, but populating a global array with positional parameters is much easier than that, and has no side-effects.
$ bash -O extdebug -s foo bar
$ f() {
> declare -p BASH_ARGC BASH_ARGV
> echo ${BASH_ARGV[BASH_ARGC[0] + BASH_ARGC[1] - 1]}
> }
$ f 42 69
declare -a BASH_ARGC=([0]="2" [1]="2")
declare -a BASH_ARGV=([0]="69" [1]="42" [2]="bar" [3]="foo")
foo
SCRIPT_ARG=$1
function f() {
FUNC_ARG=$1;
echo $SCRIPT_ARG # Prints "abc"
echo $FUNC_ARG # Prints "def"
}
f "def"
f "$1"$1,$@and$*are overridden in the function by the function's context. You could create an array outside the function containing the command-line arguments –args=("$@")— and reference that within the function.