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4 votes
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Asymptotic behavior of $L^2$ norm for increased matrix dimensions

If you take $\|\cdot\|_2$ to mean the operator $2$-norm (the norm induced by the Euclidean vector norm), then for Hermitian matrices this is just the largest absolute value of an eigenvalue. In your ...
138 Aspen's user avatar
  • 1,367
1 vote

Complexity of $Th(\langle \mathbb{Z}; + , 1 \rangle)$ same as $Th(\langle \mathbb{Z}; + \rangle)$?

$\def\Z{\mathbb Z}\DeclareMathOperator\Th{Th}\DeclareMathOperator\lcm{lcm} \def\E#1{\mathrel{\mathrm E_{#1}}}$Yes, $\Th(\Z,+,1)$ has the same complexity as $\Th(\Z,+)$. This follows from the following ...
Emil Jeřábek's user avatar

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