3
$\begingroup$

I was studing linear algebra, being more specific linear transformation, I think that a composite function is a linear transformation, but how to prove it?

$\endgroup$
3
  • $\begingroup$ Please specify what you mean by a "composite function". $\endgroup$ Commented Jun 6, 2015 at 4:40
  • $\begingroup$ Presumably the composition of two linear transformations. What is your definition of a linear transformation? What happens when you plug the results of one transformation, into another? $\endgroup$ Commented Jun 6, 2015 at 4:43
  • $\begingroup$ Let $f:X\to Y$ and $g:Y\to Z$ be linear maps/transformations, then $f\circ g:X\to Z$ is again a linear map. By definition of a linear map you need to proof that: $f(g(x+y))=f(g(x))+f(g(y))$ and $f(g(ax))=af(g(x))$ for any scalar a. $\endgroup$ Commented Jun 6, 2015 at 4:50

1 Answer 1

5
$\begingroup$

If $f: A \to B, g: B \to C$ are $2$ linear transformations we can show that $g\circ f: A \to C$ is also a linear transformation. To this end, let $x,y \in A$ and note that $$(g\circ f)(x+y) = g(f(x+y)) = g(f(x)+f(y)) = g(f(x))+g(f(y)=(g\circ f)(x)+(g\circ f)(y)$$and $$(g\circ f)(rx)=g(f(rx))=g(rf(x))=rg(f(x))=r(g\circ f)(x).$$ These identities show the composition is linear.

$\endgroup$

Start asking to get answers

Find the answer to your question by asking.

Ask question

Explore related questions

See similar questions with these tags.